In the sequence an = 2n2 + 1, what is 4a8 + 5a3?
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The value of (4a₈+5a₃) = 611
Given:
a = 2n² + 1
To find:
The value of 4a₈ + 5a₃
Solution:
Given that nth term in sequence = 2n² + 1
The 8th term a₈
⇒ a₈ = 2(8)² + 1 = 2(64) + 1 = 128 + 1 = 129
⇒ 4a₈ = 4(129) = 516
The 3rd term a₃
⇒ a₃ = 2(3)² + 1 = 2(9) + 1 = 18 + 1 = 19
⇒ 5a₃ = 5(19) = 95
4a₈ + 5a₃ = 516 + 95 = 611
The value of (4a₈+5a₃) = 611
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