in the sequence of 3 consecutive natural numbers, product of two alternate numbers is 1 less than the square of middle number.
using this find
a) 99×101=?
b) 45 x 51 =?
c) 199 ×201=?
Answers
Answered by
3
Answer
- 99*101=9999
- 49*51= 2499
- 199*201=39999
Answered by
3
Answer:
99*101=9999
49*51= 2499
199*201=39999
Step-by-step explanation:
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