Math, asked by aiswaryap920, 2 months ago

in the sequence of 3 consecutive natural numbers, product of two alternate numbers is 1 less than the square of middle number.
using this find
a) 99×101=?
b) 45 x 51 =?
c) 199 ×201=?

Answers

Answered by taniajanagal61

3

Answer

99*101=9999
49*51= 2499
199*201=39999

Answered by Anonymous

3

Answer:

99*101=9999

49*51= 2499

199*201=39999

Step-by-step explanation:

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