Math, asked by iftekharahemmad, 1 month ago

in the sequence of number 1, 2, 11, 22, 111, 222,... the sum of the digits in the 999th term is? explain in details​

Answers

Answered by lohitjinaga
0

hope it is your helping...

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Answered by arshikhan8123
3

Concept:

Series is a sequence of numbers following a particular pattern.

Given:

We are given a series:

1, 2, 11, 22, 111, 222,...

Find:

We need to find the sum of the digits in the 999th term.

Solution:

We can see that:

First term = 1

3rd term = 11

5th term =111

And so on....

The pattern is:

Every ( 2n + 1 )th term has ( n + 1 ) number of 1 in it.

So, for the 999th term,

2 n + 1 = 999

2 n = 998

n = 499

n + 1 = 499 + 1 = 500

So, 999th term will have 500 ones in it.

So, the sum will be:

500 × 1 = 500.

Therefore, we get that the sum of the digits in the 999th term will be 500.

#SPJ2

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