in the sequence of number 1, 2, 11, 22, 111, 222,... the sum of the digits in the 999th term is? explain in details
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Concept:
Series is a sequence of numbers following a particular pattern.
Given:
We are given a series:
1, 2, 11, 22, 111, 222,...
Find:
We need to find the sum of the digits in the 999th term.
Solution:
We can see that:
First term = 1
3rd term = 11
5th term =111
And so on....
The pattern is:
Every ( 2n + 1 )th term has ( n + 1 ) number of 1 in it.
So, for the 999th term,
2 n + 1 = 999
2 n = 998
n = 499
n + 1 = 499 + 1 = 500
So, 999th term will have 500 ones in it.
So, the sum will be:
500 × 1 = 500.
Therefore, we get that the sum of the digits in the 999th term will be 500.
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