Question

In the series of reaction $C_6H_5NH_2 \xrightarrow[0-5^o C]{NaNO_2 /HCl} X \xrightarrow[H_2O]{HNO_2} Y + N_2 + HCl$ X and Y are respectively
(a) C₆H₅ - N = N - C₆H₅, $C_6H_5N_2^{\oplus}Cl^{\ominus}$
(b) $C_6H_5N_2^{\oplus}Cl^{\ominus}$, C₆H₅ - N = N - C₆H₅
(c) $C_6H_5N_2^{\oplus}Cl^{\ominus}$, C₆H₅NO₂
(d) C₆H₅NO₂, C₆H₆

Answer 1

Hey mate....

here's the answer. ..

Option B

Hope this helps❤

Answer 2

Here is Your Answer

Quetion :- In the series of reaction $C_6H_5NH_2 \xrightarrow[0-5^o C]{NaNO_2 /HCl} X \xrightarrow[H_2O]{HNO_2} Y + N_2 + HCl$ X and Y are respectively

Answer :- $C_6H_5N_2^{\oplus}Cl^{\ominus}$, C₆H₅ - N = N - C₆H₅

Hope it Heplfull Answer.