Math, asked by requirosoarlumme, 5 hours ago

In the set of real numbers R there is an operation defined as: x * y = 3 (x3+y3)2. prove that (R,x) is an Abelian Group.

Answers

Answered by Jasleen0599
0

Assume  (G,∗,e)  is any group with a binary operation  

∗: G×G→G  and neutral element  e, and  H  is a set that admits a bijection  

h: H -> G.

Then we may define a binary operation  

□: H×H→H  by  a□b:=h−1(h(a)∗h(b))  

which makes  H  a group with neutral element  f:=h−1(e): For any an∈H  we have by definition

a□f = h − 1 (h (a) ∗ h (f)) = h − 1 (h (a) ∗ e ) = h − 1 (h (a) ) = a ,

and along the same lines also  f□a=a , Thus  f  is the neutral element of  H . Now ,

b=h−1(h(a)inv)  

is indeed the inverse element of  a∈H , where I have denoted taking an inverse element in  G  with respect to the group operation by the subscript  inv  in order to avoid confusion with the use of the superscript  −1  for the inverse map  h−1 :

a□b = h − 1 (h (a) ∗ h (b)) = h − 1 (h (a) ∗ h (a) inv) = h − 1 (e) = f ,

and along the same lines also b□a=f  is shown. It is left to the reader to verify the binary operation  □  on  His associative. Thus  (H,□,f)  is a group.

The group structure on G is transferred to H via the bijection h: H -> G, and by construction  H  is isomorphic to  G . Note that the set  H  is not assumed to be endowed with any structure before lifting the group structure of  G  to  H.

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