In the setup given below, If a bullet of mass m = 10 g moving with a velocity, V. = 400 m/s strikes the block of
mass M 1.99 kg and embeds in it, calculate the heighth through which the block sivings after impact.
0.987
0.77
0.63 |
0.56
Answers
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Answer:
120 m/ s
Explanation:
A bullet of mass 10g moving horizontally with a velocity of 400 m/s strikes a wooden block of mass 2 kg which is suspended by a light inextensible string of length 5 m. As a result, the centre of gravity the block is found to rise a vertical distance of the block is found to rise a vertical distance of 10 cm. The speed of the bullet after it emerges out horizontally from the block will be:
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