In the shown figure blocks A and B are 1kg each and surfaces are all smooth.Spring constant is k=60N/cm.The system is in equilobrium.The minimum mass of block C for which when block C is suddenly removed the block A leaves contact from support is
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Answer :-
→ 75/100 or 075
Explanation :-
Le theta is @ ,
For block A
Time of flight t ' = 2u sin@/g ......(1)
For block B
Time of flight t = 2 u cos@/g ....(2)
Now ,
We know that ,Range = 480
→ u^{2} sin 2@/g = 480
→ sin 2@= 0.96
→ @ ( theta) ~ 36.86 or in round 37°
therefore ,
Ratio of time of flight of both is
→ sin@/ cos @ = tan @
→ tan 37° = 0.75
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