Question

in the shown in figure 2.47 find the potential difference across thecells E1 and E2​

Answer 1

Answer:

this is answer

Explanation:

R

eff

=r

1

+r

2

+4.5+

9

3×6

=1.5+4.5+2=8Ω

I=

8

E

2

−E

1

=0.5A

P.DacrossE

1

=E

1

+Ir

1

=4+0.5+0.5=4.25V

E

2

=E

2

−Ir

2

=8−0.5=7.5V