Question

In the shown mass pulley system, pulleys and string are massless. The one end of the string is pulled by the force F=2mg. The acceleration of the block will be

Answer 1

Answer:

1)  Let the tension in the string attached to the Force be T.

Then, T=F=2mg

2) Now,

As shown in figure attached,

Using Force equation,

2T-mg=ma

=>2*2mg-mg=ma

=>4mg-mg=ma

=>3mg=ma

=>a=3g

Hence, the acceleration of block of mass 'm' is 3g in upward direction

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Answer 2

Answer:

Answer:

1)  Let the tension in the string attached to the Force be T.

Then, T=F=2mg

2) Now,

As shown in figure attached,

Using Force equation,

2T-mg=ma

=>2*2mg-mg=ma

=>4mg-mg=ma

=>3mg=ma

=>a=3g

Hence, the acceleration of block of mass 'm' is 3g in upward direction

Explanation:

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