Question

in the side figure, AD bisects angle A and AD is perpendicular to BC.
(a) Is ∆ADB congruent ∆ADC? State the three pairs of corresponding parts.
(b) Is it true to say that BD=CD?​

Answer 1

Answer:

in ∆ADB and ∆ADC,

AD=AD (common)

angle ADB=ASC (90°each)

angle DAB=DAC (given)

so, ∆ADB congurent ∆ADC (ASA)

BD=CD (CPCT)

Hence proved

Hope this helps you...(•‿•)

Answer 2

Answer:

In ∆ADB and ADC

AD=AD(common)

angle ADB=ASC (90°each)