In the side figure, PL is perpendicular to OB and PM is perpendicular to OA such that PL=PM. Is OC a bisector of angle AOB ?Why ?
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In triangle POL and POM.
PL = PM (given)
POPO (common)
Angle L = Angle M (each 90)
Therefore, POL is congruent to POM.
By CPCT,
OL = OM.
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