Question

In the simple subtraction problem below, some single digits (not necessarily distinct) are replaced by letters. Find the value of 6*A + 5*B + 2*C*D.
A1C5
- 1B67
--------------
656D

Answer 1

Answer: 121

Step-by-step explanation:

15-7=8(D)

(C+10)-(6+1)=6⇒C=3

(1+10)-(B+1)=5⇒B=5

A-(1+1)=6⇒A=8

So the value will be:

6*8+5*5+2*3*8=121 (ans)

Answer 2

Answer:

Value of given Expression is 121.

Step-by-step explanation:

We need to find the value of 6 × A + 5 × B + 2 × C × D

A,B,C,D are missing digits in the given subtraction.

 A1C5

-  1B67

--------------

  656D

Usig rules of subtraction,

5 - 7 = D. Since 5 is smaller than  ⇒ D = 15 - 7 = 8

Now, C = 6 + 6 + 1 = unit place of 13 .i.e., C = 3

Now, B = 10 - 5 = 5

last, A = 6 + 1 + 1 = 8

Thus, 6 × A + 5 × B + 2 × C × D = 6 × 8 + 5 × 5 + 2 × 3 × 8 = 48 + 25 + 48 = 121

Therefore, Value of given Expression is 121.