Question

In the simple subtraction problem below , sum single digits (not necessarily distinct) are replace by letters , find the value of 7*a + 7*b +6*c*d. a 7 c 2 - 4 b 6 8 5 4 3 d

Answer 1

Answer:

A9C5

-2B79

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6336 since,15-9=6. from there,D=6 and solving all,we get A=8,B=5,C=1.

So 2*8+2*5+4*1*6=505 years agoHelpfull: Yes(29) No(0)50 is ans ,.......5 years agoHelpfull: Yes(1) No(0)a) 50

A=8, B=5, C=1, D=65 years agoHelpfull: Yes(1) No(0)A9C5

-2B79

.................

6336

so

A=8

B=5

C=1,and

D=6

so

2A+2B+4CD=2*8+2*5+4*1*6=50

so option a is correct.5 years agoHelpfull: Yes(1) No(0)Thats right ... it is 50...5 years agoHelpfull: Yes(1) No(0)A9C5

2B79

=====

633D so A9c5= 8915 2B79=2579=6336 so A=8,B=5,c=1 D=6 so 2*8+2*5+4*1=50 Ans5 years agoHelpfull: Yes(1) No(0)D=6

C=1

B=5

A=7

2*7+2*5+4*1*6=48

5 years agoHelpfull: Yes(1) No(4)A=8,B=5,C=1,D=6 then ans is 50

5 years agoHelpfull: Yes(1) No(0)A9C5

-2B79

---------

633D

NOW, D=6 as 15-9=6, and c-(7+1)=3, c=11 i.e value of c in the expression is 1, and b=5 as 9-(b+1)=3, and A=8 as A-2=6

so 2*A +2*B +4*C*D=16+10+24=504 years agoHelpfull: Yes(1) No(0)A=8,B=5,C=1,D=6

SO, ANS= 50