Question

In the situation given, a force of 100 N is acting on a black
placed on rough horizontal surface as shown in the ligure. The block does
not slide. If the angle of friction is found to be tan
Find the value of n.
10kg
Take g = 10 m/s​

Answer 1

YUP! HERE IS YOUR ANSWER!!!!

In horizontal direction, two forces are acting on the block : 100 N force and friction force (f)

In horizontal direction, two forces are acting on the block : 100 N force and friction force (f)f=μN=μmg=0.5×10×10=50N

In horizontal direction, two forces are acting on the block : 100 N force and friction force (f)f=μN=μmg=0.5×10×10=50NSo, net force acting on the block in horizontal direction = 100 N-50 N = 50 N

In horizontal direction, two forces are acting on the block : 100 N force and friction force (f)f=μN=μmg=0.5×10×10=50NSo, net force acting on the block in horizontal direction = 100 N-50 N = 50 Nacceleration of the block = Net force / mass of block = 50 N/10 kg = 5 ms

In horizontal direction, two forces are acting on the block : 100 N force and friction force (f)f=μN=μmg=0.5×10×10=50NSo, net force acting on the block in horizontal direction = 100 N-50 N = 50 Nacceleration of the block = Net force / mass of block = 50 N/10 kg = 5 ms −2

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Answer 2

I hope it will help you.Thank you.Have a nice day