Question

in the situation given a force of 100N is acting on a block placed on rough horizontal surface as shown in the figure the block does not slide if the angle of friction is found to be
${tan}^{ - 1} \frac{1}{n}$
take g =10 m/s^2______
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Answer 1

Taking components of force,

Fcos37*mu=Fsin37

mu=tan37=3/4

Answer 2

Correct ans is

Net downward force=Normal force

10*10+100sin37=Normal

=100(1+3/5)

100*8/5=160N

Friction=mu*160

100cos37=mu*160

100*4/5=160mu

mu=80/160

mu=1/2