Question

In the situation shown in figure, the current is decreasing at a constant rate of 3 A/s. The potential difference between A and B, when current in the circuit is 5 A, will be ?
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Answer 1

Answer:

please provide the figure

Explanation:

please provide the figure as mentioned in the question

Answer 2

In the situation shown in figure, the current is decreasing at a constant rate of 3 A/s.

We have to find the potential difference between A and B, when current in the circuit is 5 A.

as the current decreasing at the rate of 3A/s from A to B, induced emf will be developed in such a way that terminal B be positive and and terminal A be negative.

now the potential difference, $V_B-V_A$ = iR + V + L (-di/dt)

here, i = 5A , R = 5Ω , V = 10 volts L = 4H and di/dt = 3A/s

∴ potential difference between A and B = 5A × 5Ω + 10 volts - 4H × 3A

= 25 + 10 - 12

= 23 V

Therefore the potential difference between A and B will be 23volts.