Question

In the situation shown the currents through 3 ohm and 2 ohm resistances are in the ratio

Answer 1

Watch the answer patiently,

R in series=3ohms
R in parallel=9/4ohms

Total R through it is given by;

R=R(p):R(s)
=3/4

Therefore by ohms law;

V=IR
I=V/R
I=1/R. (V is constant)
I =1/3/4
I=1*4/3
I=4:3. Ans

Answer 2

Given:

Resistance in series,

= 3Ω

Resistance in parallel,

= $\frac{9}{4} \Omega$

To find:

We have to shown that the currents through 3Ω and 2Ω resistances are in the ratio.

Solution:

According to the question,

⇒  $R = R (p):R (s)$

        $=3:4$

        $=\frac{3}{4}$

According to the Ohms law,

⇒  $V=I\times R$

or,

⇒  $I=\frac{V}{R}$

On substituting the value in the above formula an where V is constant, we get

⇒     $=\frac{1}{\frac{3}{4} }$

⇒     $=1\times \frac{4}{3}$

⇒     $=\frac{4}{3}$

⇒     $=4:3$

Thus the correct answer is "4:3".