Question

in the solid state .PCl5 as an ionic solid. the hybridisation of phosphorus in the cationic and anionic part are respectively?

Answer 1

the correct answer should be sp3 and sp3d2 because the phosphorous in PCl5 exists in both (PCl4)+ and (PCl6)- to increase interionic bond attraction.....

Answer 2

Answer:

The correct option is (2) $sp^{3}$, $sp^{3} d^{2}$

Explanation:

• It exists as an ionic solid, $[PCl_{4}]^{-}$ [$[PCl_{6}]$], in the solid-state.
• The $[PCl_{4}]^{-}$ cation has a $sp^{3}$  hybridized structure and is tetrahedral.
• The anion [PCl6] has an octahedral shape and $sp_{3} d_{2}$ hybridization.
• Atomic orbitals with comparable energies hybridize.
• The number of atomic orbitals mixing equals the number of hybrid orbitals that are created.
• Not every orbital with half of its volume filled must participate in hybridization. Orbitals that are fully filled and have somewhat varying energies can also take part.
• Only when a bond is formed does hybridization take place, not when a gaseous atom is left alone.
• If the molecule's hybridization is known, the shape of the molecule can be predicted.
• In a hybrid orbital, the larger lobe is always positive while the smaller lobe on the other side is always negative.

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