in the space station, liquid ammonia is used to transfer heat. if 100g of liquid ammonia evaporates, then how much heat will be removed? (ΔHf = 5.65 kJ/mol)
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Given mass of amonia , NH₃ = 100g
We know, molecular mass of NH₃ = 17g/mol
so, number of moles in 100g = given weight/molecular weight = 100/17
Question again, given heat of vaporization of NH₃ = 5.65 kJ/mol
so, heat will be removed = heat of vaporization × number of moles
= 5.65 × 100/17 = 33.23 KJ
Hence answer is 33.23 KJ
We know, molecular mass of NH₃ = 17g/mol
so, number of moles in 100g = given weight/molecular weight = 100/17
Question again, given heat of vaporization of NH₃ = 5.65 kJ/mol
so, heat will be removed = heat of vaporization × number of moles
= 5.65 × 100/17 = 33.23 KJ
Hence answer is 33.23 KJ
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