In the square PQRS an equilateral triangle OPQ is drawn. Prove that OPS ≅ OQR
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Step-by-step explanation:
in a square diagonals are equal please see the attachment
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Answer:
Proved
Step-by-step explanation:
in ΔOPQ
OP=OQ [sides of equilateral triangle]
PS=QR [sides of a square]
angle OSP=angle ORQ
Therefore,
ΔOPS ≈ ΔOQR. [By SAS test of
congruency]
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