Math, asked by saisruthikoppisetti, 2 months ago

In the standard xy plane, center of a circle lies on the line y = x at a
distance of 732 from the origin in the 1st quadrant. If the x-axis is a tangent
to the circle, which of the following is the equation of the circle?

a) (x -- 4)2 + (y - 2)2 = 8
b) (x - 2)2 + (y - 2)2 = 16
c) (x – 4)2 + (y – 4)2 = 16
d)(x – 4)2 + (y - 2)2 = 32

Answers

Answered by harekrishna26
3

Answer:

center of a circle lies on the line y = x at a

distance of 732 from the origin in the 1st quadrant

i think u type distance 732 as wrong because from option for me knowing that u type distance wrongly . anyhow in picture i assumed distance d

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