Question

In the "Strange" family, each daughter has the same number of brothers as she has sisters. Each son has twice as many sisters as he has brothers. How many sons and daughters are in the family? * I will mark you brainliest if u answer this. correct and quick

Answer 1

Given:

1. Each daughter has the same number of brothers as she has sisters.

2. Each son has twice as many sisters as he has brothers.

To find:

The number of sons and daughters in the family

Solution:

Let the number of sisters be S and brothers be B

According to the first condition :

Each daughter has equal number of sisters and brothers

So, we can form the equation-

S-1 = B -------(i)

According to the second condition:

Each son has number of sisters twice to that of brothers, so the equation is-

2(B-1)= S-------(ii)

Solving the two equations (i) and (ii):

2(S-1-1) = S( replacing the value of B in equation ii by S-1)

So, S= 4 (sisters/daughters)

So, B = S-1 = 3 (sons/brothers)

There are three sons and four daughters in the family.

Answer 2

Answer:

There are 3 sons and 4 daughters in the family