Question

In the sum 3+33+333+3333+...........2015 terms the number formed by taking the last four digits in that order is​

Answer 1

3 (1 +11+111+1111......)

3/9(9 +99+999+9999....)

3/9( 10-1; 100-1; 1000-1.....)

3/9(10+100+1000.....)*(1+1+1+1....2005tterms)

3/9(apply gp)

You got your answer

Answer 2

Step-by-step explanation:

Be more specific please...!!!