In the super market there are five shopkeepers A, B, C, D,
E. If shopkeeper A sells his 2/3 of products in a day, B
sells 3/7 of products, C sells 4/5 of products in a day, D
sells 5/6 of products in a day and E sells 7/8 of products
in a day, who sells more products in a day? Cut 5 equal
circles and represent each fraction on the circles and find
the largest fraction and the smallest fraction.
Answers
Answer:
Step-by-step explanation:
E
Given :
There are 5 shopkeeper a ,b ,c ,d ,e
A sells 2/3 product in a day
B sell 3/7
C sell 4/5 ,
D sell 5/6
E sell 7/8
To Find : who sell more product ?
Solution :
To find who sell more make the denominator of all fractions equal .
so, take LCM of all denominators
Thus LCM of 3,7,5,6,8 =840
So make denominators of all fraction 840
A sells
B sells
C sells
D sells
E sells
Thus E sells more product in a day
ans
E
Given :
There are 5 shopkeeper a ,b ,c ,d ,e
A sells 2/3 product in a day
B sell 3/7
C sell 4/5 ,
D sell 5/6
E sell 7/8
To Find : who sell more product ?
Solution :
To find who sell more make the denominator of all fractions equal .
so, take LCM of all denominators
Thus LCM of 3,7,5,6,8 =840
So make denominators of all fraction 840
A sells
B sells
C sells
D sells
E sells
Thus E sells more product in a dayStep-by-step explanation: