Question

In the super market there are five shopkeepers A, B, C, D,
E. If shopkeeper A sells his 2/3 of products in a day, B
sells 3/7 of products, C sells 4/5 of products in a day, D
sells 5/6 of products in a day and E sells 7/8 of products
in a day, who sells more products in a day? Cut 5 equal
circles and represent each fraction on the circles and find
the largest fraction and the smallest fraction.​

Answer 1

Answer:

Step-by-step explanation:

E

Given :  

There are 5 shopkeeper a ,b ,c ,d ,e

A sells 2/3 product in a day

B sell 3/7

C sell 4/5 ,

D sell 5/6

E sell 7/8

To Find : who sell more product ?

Solution :

To find who sell more make the denominator of all fractions equal .

so, take LCM of all denominators

Thus LCM of 3,7,5,6,8 =840

So make denominators of all fraction 840

A sells  

B sells  

C sells  

D sells  

E sells  

Thus E sells more product in a day

Answer 2

ans

E

Given :  

There are 5 shopkeeper a ,b ,c ,d ,e

A sells 2/3 product in a day

B sell 3/7

C sell 4/5 ,

D sell 5/6

E sell 7/8

To Find : who sell more product ?

Solution :

To find who sell more make the denominator of all fractions equal .

so, take LCM of all denominators

Thus LCM of 3,7,5,6,8 =840

So make denominators of all fraction 840

A sells  

B sells  

C sells  

D sells  

E sells  

Thus E sells more product in a dayStep-by-step explanation: