Question

In the supermarket there are 5 shopkeeper a ,b ,c ,d ,e if A sells 2/3 product in a day ,b sell 3/7, c sell 4/5 ,d sell 5/6 and e sell 7/8 of product in a day who sell more product ??

Answer 1

Answer:

E

Step-by-step explanation:

Given :  

There are 5 shopkeeper a ,b ,c ,d ,e

A sells 2/3 product in a day

B sell 3/7

C sell 4/5 ,

D sell 5/6

E sell 7/8

To Find : who sell more product ?

Solution :

To find who sell more make the denominator of all fractions equal .

so, take LCM of all denominators

Thus LCM of 3,7,5,6,8 =840

So make denominators of all fraction 840

A sells $\frac{2}{3} *\frac{280}{280} =\frac{560}{840}$

B sells $\frac{3}{7} *\frac{120}{120} =\frac{360}{840}$

C sells $\frac{4}{5} *\frac{168}{168} =\frac{672}{840}$

D sells $\frac{5}{6} *\frac{140}{140} =\frac{700}{840}$

E sells $\frac{7}{8} *\frac{105}{105} =\frac{735}{840}$

Thus E sells more product in a day

Answer 2

Answer:

E

Step-by-step explanation:

Given:

There are 5 shopkeeper a, b, c, d, e

A sells 2/3 product in a day

B sells 3/7 product in a day

C sells 4/5 product in a day

D sells 5/6 product in a day

E sells 7/8 product in a day

To Find : who sell more product?

Solution :

Make the denominator of all fractions equal to see who sells the most.

As a result, take the LCM of all denominators.

Thus, LCM of 3,7,5,6,8 =840

So make denominators of all fraction 840

A sells $\frac{2}{3}\times\frac{280}{280}=\frac{560}{840}$

B sells $\frac{3}{7}\times\frac{120}{120}=\frac{360}{840}$

C sells $\frac{4}{5}\times\frac{168}{168}=\frac{672}{840}$

D sells $\frac{5}{6}\times\frac{140}{140}= \frac{700}{840}$

E sells $\frac{7}{8}\times\frac{105}{105}=\frac{735}{840}$

Thus E sells more product in a day.

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