Math, asked by krishna6755, 11 months ago

In the supermarket there are 5 shopkeepers A, B, C, Dand E. If shopkeeper A sells his 2/3 of product in a day, B sells 3/7of product, C sells 4/5 of product in a day, D sells 5/6 of product in a day and E sells 7/8 of product in a day, who sells more product in a day?​

Answers

Answered by Prachi1146
12

Answer:

Shopkeeper E sells more product in a day.

Step-by-step explanation:

A sells=2/3 of product

B sells= 3/7 of Product

C sells= 4/5 of product

D sells=5/6 of product

E sells =7/8 of product

We will take LCM .

LCM= 840

So,

A sells=2/3×280/280=560/840

B sells= 3/7×120/120=360/840

C sells= 4/5×168/168=672/840

D sells= 5/6× 140/140=700/840

E sells=7/8× 105/105=735/840

therefore, shopkeeper E sell more product in a day.

Hope this will help u.

Answered by vinod1978888
1

Answer:

Step-by-step explanation:

thank you

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