Question

in the supermarket there are five shopkeeper a b c d e f shopkeeper a sells 2 by 3 of product in a day B cells 3 by 7 product in a day she sells for by 5 of product in a day the cell 5 by 6 of product in a day and e-cell 7 buy a product in a day who sell more product in a day but 5 equal circles and present each fraction on the circle and find the largest fraction and the smallest fraction.

Answer 1

Answer:

Multiply each no. By 840 as it is the l.c.m.

A=2*840/3

B=3*840/7

C=4*840/5

D=5*840/6

E=7*840/8

Therefore

A=2*280=560

B=3*120=360

C=4*168=672

D=5*140=700

E=7*105=735

Therefore shopkeeper E sold more products The lowest sale is of B

Answer 2

Solution is in the attachment