In the Supermarket there are five
Shopkeepers A, B, C, D,E. If Shopkepas
A Sells his, 2/3 of products in a day
B. sells 377 of products & C. selts
4/5 of products in a day & Di sello
5/6 products in a day and E
sells 7/8 of products in a
day , who
sella
more products in a
day of cut
5 equal circles and Represent each
fraction on circles
using
color
papers
Answers
Answer:
E sells more
Step-by-step explanation:
Given :
There are 5 shopkeeper a ,b ,c ,d ,e
A sells 2/3 product in a day
B sell 3/7
C sell 4/5 ,
D sell 5/6
E sell 7/8
To Find : who sell more product ?
Solution :
To find who sell more make the denominator of all fractions equal .
so, take LCM of all denominators
Thus LCM of 3,7,5,6,8 =840
So make denominators of all fraction 840
A sells \frac{2}{3} *\frac{280}{280} =\frac{560}{840}
3
2
∗
280
280
=
840
560
B sells \frac{3}{7} *\frac{120}{120} =\frac{360}{840}
7
3
∗
120
120
=
840
360
C sells \frac{4}{5} *\frac{168}{168} =\frac{672}{840}
5
4
∗
168
168
=
840
672
D sells \frac{5}{6} *\frac{140}{140} =\frac{700}{840}
6
5
∗
140
140
=
840
700
E sells \frac{7}{8} *\frac{105}{105} =\frac{735}{840}
8
7
∗
105
105
=
840
735
Thus E sells more product in a day