Question

in the supermarket there are five shopkeepers ABCD and see if A shopkeeper sells 2 by 3 of product in a day and B cells 3 by 7 of the product in a day and see sells 455 a product in a De De sells 5 by 6 of product in a day and easy sells 7 by 8 of product in a day Who sells more product in a day but 5 equal circles and present each fraction on the circle and find the largest fraction and and the smallest fraction

Answer 1

Answer:

Multiply each no. By 840 as it is the l.c.m.

A=2*840/3

B=3*840/7

C=4*840/5

D=5*840/6

E=7*840/8

Therefore

A=2*280=560

B=3*120=360

C=4*168=672

D=5*140=700

E=7*105=735

Therefore shopkeeper E sold more products The lowest sale is of B

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