In the synthesis of ammonia from nitrogen and hydrogen gases, if 6*10⁻² moles of hydrogen disappears in 10 minutes ,the number of moles of ammonia formed in 0.3 minutes is
(A) 1.8*10⁻²
(B) 1.2*10⁻³
(C) 4*10⁻²
(D) 3.6*10⁻²
Answers
Answered by
3
━━━━━━━━❪❐━━━━━━━
option b
Attachments:
Answered by
1
Answer:
correct answer is option B
Explanation:
∵ In 10 min, the number of H^2 disappears =6×10^−2
∴ In 0.3 min, the number of moles of H^2 disappear= (6×10^−2 ×(0.3))/10
=1.8×10^−3
N2 + 3H2 ⇌ 2NH3
⇒ 1/3[ Rate of disappearance of H2]
= 1/2 [ Rate of formation of NH3]
∴ Rate of formation of NH3 = 2/3×(1.8×10^−3)
=1.2×10^−3 mol NH3
∴1.2×10^−3 moles of NH3 are formed.
Similar questions