In the system shown below, a constant force F is applied. The reaction offered by m, upon m, is
F
m, m2
m F
(1)
mi + m2
(2)
m F
m, + m2
(3)
m, -m F
mz
(4) zero
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Step-by-step explanation:
For M1 =F-f =M1a. - eq (1)
For M2 = f= M2a. -eq (2)
Add eq 1 and 2
F-f+f = m1a+m2a
F= (m1+m2)a
a = F/m1+m2
equation 2 =
f = m2f/m1+m2
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