Question

In the system shown in the figure the acceleration of the 1 kg mass and the tension in the string connecting between a and b is

Answer 1

Answer:

tension between a and b is 10 N

acceleration of 1 kg block is 10/7 m/s^2

Answer 2

Answer:

The tension between A and B will be 11N and the acceleration will be g/6 m/s^2.

Explanation:

Since the ropes are connected by the same pulley hence the tension between B and C is T. Let the tension between the A and B is T1.

So, for the block C 3a = T - 3g. Again for the block B 3a = 4g - T. And for the mass C a = T1  - g.

So, on taking the tension T common then 6a = g then the value of a is g/6 m/s^2. So, putting the g/6 in the last equation we will get the T1 is 7g/6 which will approximately be equal to 11 N.