Question

In the system shown the 5kg block is released from the rest. The pulley and spring r massless n friction is absent everywhere. The force constant of the spring if 40N/m , speed of 5kg block when 2kg block leaves contact with the ground is???​

Answer 1

Explanation:

let X be tension in Spring

2 kg mass leaves contact with the ground

kx= 2g

x=2g/k

=1/2m

According to law of conservation of energy

mgx=1/2k^2+1/2mv^2

solve the equation for v and you will get the answer v= 2√2 m/s

Answer 2

Explanation:

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