Question

In the system shown the acceleration of the wedge of mass 5m is zero if angle '@' of wedge
are smooth)
then calculate x (all surfaces
m
5m​

Answer 1

Explanation:

Let a

′

be the acceleration towards left.

From the Diagram,

T−Ma

′

=Ma−−−−−(1)

2Ma

′

cos60

0

+2Mgsin60

0

−T=2Ma−−−−−(2)

=>Ma

′

+

3

Mg−Ma

′

=3Ma

=>a=

3

g

Now, acceleration for the block 5,

5Ma

′

+M(a+a

′

)=2M[acos60

0

−a

′

]

6Ma

′

+Ma=−2Ma

′

+Ma

a

′

=0