In the system shown the acceleration of the wedge of mass 5m is zero if angle '@' of wedge
are smooth)
then calculate x (all surfaces
m
5m
Answers
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Explanation:
Let a
′
be the acceleration towards left.
From the Diagram,
T−Ma
′
=Ma−−−−−(1)
2Ma
′
cos60
0
+2Mgsin60
0
−T=2Ma−−−−−(2)
=>Ma
′
+
3
Mg−Ma
′
=3Ma
=>a=
3
g
Now, acceleration for the block 5,
5Ma
′
+M(a+a
′
)=2M[acos60
0
−a
′
]
6Ma
′
+Ma=−2Ma
′
+Ma
a
′
=0
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