Question

In the throw of three coins simultaneously find probability of getting at least one head

Answer 1

Answer:

Step-by-step explanation:

Total outcomes=(HHH),(HTH),(TTH),(THT),(TTT),(HHT)

Possible outcomes = (HHH),(HTH),(TTH),(THT),(HHT)

Probablility(at least on head)=possible outcomes/total outcomes

= 5/6

Ans = 5/6