Question

In the time that it takes one car to travel 93 km, a second car travels 111 km. If the average speed of the second car is 12 km/h faster than the speed of the first car, what is the speed of each car?

Answer 1

$\mathfrak{\huge{Hi!}}$

$\sf{Let\:time\:be\:same\:for\:both\:cars}$

$\sf{Let\:speed\:of\:first\:car = x\:km/hr}$

$\sf{Distance\:travelled = 93\:km}$

Time taken by first car = $\tt{\frac{93}{x}}$

$\sf{Let\:speed\:of\:second\:car = y\:km/hr}$

$\sf{Distance\:travelled = 111\:km}$

Time taken by second car = $\tt{\frac{111}{y}}$

Time is same, therefore, we can write :

$\tt{\frac{93}{x} = \frac{111}{y}}$

=》 $\tt{y = \frac{111x}{93}}$ ...(1)

According to the question :

=》 y = x + 12 ...(2)

Put (1) in (2)

=》 $\tt{\frac{111x}{93} = x + 12}$

=》 $\tt{111x = 93x + 1116}$

=》 $\tt{x = 62 km/hr}$

y = 74 km/hr

Hope it Helps!