Question

In the titration of Fe (II) vs Ce (IV), the number of electrons involved is ______.

a) One b) Five c) Eight d) Three

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Answer 1

Answer:

In the titration of Fe (II) vs Ce (IV), the number of electrons involved is option(a) one.

Explanation:

Given: Titration of Fe(II) and Ce(IV)

To Find: Number of electrons involved in titration.

Solution: Titration of Fe(II) and Ce(IV) is an example of redox titration. Redox titration is a laboratory method of determining the concentration of a given analyte by causing a redox reaction between the titrant and the analyte. These types of titrations sometimes require the use of a potentiometer or a redox indicator.

The equation for such titration becomes as follow:

Fe^2+(aq)+Ce^4+(aq)⇌Ce^3+(aq)+Fe^3+(aq)

In the above titration both oxidation as well as reduction occurs simultaneously hence it is redox titration. The species oxidized is Iron as oxidation state increase from +2 to +3 and species reduced is Ce.

Since in above reaction there is change in 1 electron only that is 1 electron is either lost or gained in the reaction hence the titration is an example of uni-electron system.

So, In the titration of Fe (II) vs Ce (IV), the number of electrons involved is one.

Code: #SPJ3