In the top row labeled Before Collision, the left billiard ball labeled 3 meters per second approaches the right billiard ball labeled 0 meters per second with a grey arrow pointing from the right ball to the left ball. In the bottom row labeled After Collision, the left billiard ball labeled 1 meters per second approaches the right billiard ball labeled 2 meters per second with grey arrows pointing to the right from both balls. Two balls, each with a mass of 0.5 kg, collide on a pool table. Is the law of conservation of momentum satisfied in this collision? Explain why or why not.
Answers
Answer:
Longest question
Explanation:
Mark me as brainliest answer
Answer:
Conservation of momentum in all closed systems is valid, regardless of the directions of the objects before and after they collide. Most objects are not confined to a single line, like trains on a rail. Rather, many objects, like billiard balls or cars, can move in two dimensions. Conservation of momentum for these objects can also be calculated; momentum is a vector and collisions of objects in two dimensions can be represented by axial vector components. To review axial components, revisit Vectors: Resolving Vectors into Axial Components and Vectors: Vector Addition.
Example 1
A 2.0 kg ball, , is moving with a velocity of 5.00 m/s due west. It collides with a stationary ball, , also with a mass of 2.0 kg. After the collision, ball moves off at 30° south of west while ball moves off at 60° north of west. Find the velocities of both balls after the collision.
Since ball is stationary before the collision, then the total momentum before the collision is equal to momentum of ball . The momentum of ball before collision is shown in red below, and can be calculated to be
Vectors illustrating the paths of two balls after a collision
Since momentum is conserved in this collision, the sum of the momenta of balls and after collsion must be 10.0 kg m/s west.
To find the final velocities of the two balls, we divide the momentum of each by its mass. Therefore, and .
Example 2
A 1325 kg car moving north at 27.0 m/s collides with a 2165 kg car moving east at 17.0 m/s. The two cars stick together after the collision. What is the speed and direction of the two cars after the collision?
Vectors of two cars that stick together after a collision
Example 3
A 6.00 kg ball, , moving at velocity 3.00 m/s due east collides with a 6.00 kg ball, , at rest. After the collision, moves off at 40.0° N of E and ball moves off at 50.0° S of E.
Vectors of two balls after a collision
What is the momentum of after the collision?
What is the momentum of after the collision?
What are the velocities of the two balls after the collision?
This is a right triangle in which the initial momentum is the length of the hypotenuse and the two momenta after the collision are the legs of the triangle.
Apply your understanding of the conservation of momentum in two dimensions to help Maria win a bocce ball game in this PLIX Interactive:
Summary
The conservation of momentum law holds for all closed systems regardless of the directions of the objects before and after they collide.
Momentum is a vector; collisions in two dimensions can be represented by axial vector components.
I hope so this answer helped u out