Question

In the trapezium ABCD, AB is parallel to CD and EF is a median. DC = 6 cm. EF = 4 cm, then AB is

Answer 1

Step-by-step explanation:

Given that AB = 6 cm, BC = 4 cm, CD = 11 cm and DA = 3 cm.

Draw a line parallel to AD as given in the below figure. That implies DE=6cm and EC=5cm.

Now we get a triangle EBC with sides 3,4 and 5 cms.

Area= 0.5*b*h = Sq.root( s*(s-a)(s-b)(s-c))

s= (3+4+5)/2 = 6

0.5*5*x = Sq.root (6*(6–3)(6–4)(6–5))

5/2*x = 6

x= 12/5 = 2.4cms

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