in the trapezium ABCD ab parallel to CD if ab is equal to 8 cm CD is equal to 14 cm and distance between the parallel sides is 10 cm find the area of trapezium
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sum of parallel side=8+14=22cm
distance between them is 10 cm
area of trapezium is 1/2*sum of parallel side*distance between them
1/2*22*10
=110 cm^2
distance between them is 10 cm
area of trapezium is 1/2*sum of parallel side*distance between them
1/2*22*10
=110 cm^2
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