in the trapezium, angle P = angle S =90° ,. PQ=QR = 13 cm , PS=12cm and SR =18cm. Find the area of trapezium
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PR=VI2^2+18 ^2 =v468=21.6cm
in triangle P Q R
P Q = 13,QR =13,PR=21.6cms
Area of P Q R =vs (s-a) (s-b)(s-c) (i)
s = 47.6/2=23.8
A =v 23.8x 10.8 x 10.8 x 2.2
=v 6107.2104=78.15cm2
Area of triangle PRS. (2)
bh/2 = 12xl8/2=216/2=108cm2
Area (1) + (2)->78.15 +108=186.15
Area of trapezium=186.15cm2
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Answer:
Yes uper one is right
Step-by-step explanation:
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