Question

in the trapezium, angle P = angle S =90° ,. PQ=QR = 13 cm , PS=12cm and SR =18cm. Find the area of trapezium​

Answer 1

PR=VI2^2+18 ^2 =v468=21.6cm

in triangle P Q R

P Q = 13,QR =13,PR=21.6cms

Area of P Q R =vs (s-a) (s-b)(s-c) (i)

s = 47.6/2=23.8

A =v 23.8x 10.8 x 10.8 x 2.2

=v 6107.2104=78.15cm2

Area of triangle PRS. (2)

bh/2 = 12xl8/2=216/2=108cm2

Area (1) + (2)->78.15 +108=186.15

Area of trapezium=186.15cm2

Answer 2

Answer:

Yes uper one is right

Step-by-step explanation: