Question

in the triangle ABC ,ab=10cm Ac=8 angle A =45° .find the perpendicular distance from c to ac​

Answer 1

Step-by-step explanation:

sin 45 =perpendicular /hypotenuse

1/√2=perpendicular/8

perpendicular =4√2cm

Answer 2

Answer:

$4 \sqrt{2} \: cm$

Step-by-step explanation:

It is the correct answer.