Question

IN THE TRIANGLE ABC AB =BC AND ANGLE A : ANGLE B = 4:3 FIND THE MEASURE OF C

Answer 1

Given :-

In a Given isosceles ∆ , AB = BC

And Angle A:B = 4:

Then Let Angle A = 4x , Angle B = 3x

So , Here !

Angle A = Angle C [Base angles of an isosceles∆]

So Angle C = 4x

So Angle A + Angle B + Angle C = 108°

Sum of all angles in the triangle = 180°

So , 4x + 4x + 3x = 180

11x = 180°

x = 180/11

x = 16.3 approx

Angle C = 16.3×4 = 65.2°

Answer 2

Answer:

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