Question

in the TRIANGLE ABC Ac=4cm and Ab= 3cm FIND a) the area of triangle ABC b) length of BC c) the length of altitude from A to bc

Answer 1

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Answer 2

The area of the triangle is 6 cm²

Length of BC is 5 cm

Length of Altitude from A to BC  is 2.4 cm

Step-by-step explanation:

A. Area Δ = 1/2 BH

            = 1/2 (3cm) (4cm)

            = 1/2 (12cm)

Area Δ= 6 cm²

B. BC = hypotenuse

BC = $\sqrt{x} AB^{2} +CA^{2}$

BC = $\sqrt{ 3^{2} +4^{2}$

BC = $\sqrt{ 9+6$

BC = $\sqrt{25}$

BC = 5cm

C. Sin θ = 4/5

Sin θ = 53.13010235416

Sin θ = x/3

x =2.4cm