Question

in the triangle ABC AD perpendicular to BC and angle BAD = theta if AC = 20 CM CD = 16 cm and BD = 5 cm find sin theta + cos theta​

Answer 1

Step-by-step explanation:

Here,

In the triangle ABC, AD perpendicular to BC and ∠BAD=θ if AC = 20cm and CD=16 cm and BD=5cm

Then,

Using Pythagoras theorem

AD= √(AC²-CD²)

= √{20)²-(16)²}

= √(400-256)

= √144

= 12cm

AB= √(AD²+BD²)

= √{(12)²+(5)²}

= √(144+25)

= √169

= 13cm

Now,

sinθ+cosθ = BD/AB + AD/AB

= 5/13 + 12/13

= (5+12)/13

= 17/13