In the triangle abc, ∠bac = 50 ° and the bisectors of ∠abc and ∠acb meets at p. what is the value (in degrees) of ∠bpc?
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In these type of questions there we can directly use the formula --
90 + angle A /2
So the ans would be - 90 + 50 / 2 = 90+25 =115
90 + angle A /2
So the ans would be - 90 + 50 / 2 = 90+25 =115
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