Question

in the triangle ABC, BE ⊥ AC, angle EBC=40° and angle DAC=30°​

Answer 1

Answer:

We know that,

Sum of all angles in a triangle = 180°

So, in ΔBEC

= 40 + x + 90 = 180

So, x = 50°

Now, in ΔADC-

= 50 + 30 + ∠ADC = 180

= ∠ADC = 100°

Since BC represents a straight line, sum of angles = 180°.

So, ∠ADC + y = 180

hence y = 80° since ∠ADC = 100°

By exterior angle sum theorem of the smaller triangle formed-

z = ∠DAE + ∠BEA = 90° + 30° = 120°