Question

In the triangle ABC C,D,E,F are the midpoints of the sides AB,BC and CA respectively area of traingle ABC=64 cm^2 then area of traingle DEF is​

Answer 1

Answer:

Hence, the ratio of the areas of ∆DEF and ∆ABC is 1 : 4

Answer 2

Answer:

triangles dbe , def , fec and adf are congurent therefore triangle abc = dbe+def+fec+adf

abc= 4def (.°. dbe= def =fec =adf)

1/4 abc= def

1/4×64 = def

16 cm ²= def