Question

in the triangle ABC d and e are point on side ab and ac respectively such that de parallel BC if a is equal to 2 cm is equal to 3 cm and BD is 4.5 CM then find CE​

Answer 1

Answer:

Explanation:

If a line is drawn parallel to one side of a triangle to intersect the

other two sides in distinct points, the other two sides are divided in the same ratio.

As DE∥BC  

∠ADE=∠ABC

∠AED=∠ACB

So by AAA △AED∼△ACB

Hence  

AC

AE

​  

=  

CB

ED

​  

 

∴  

AC

3.2

​  

=  

5

2

​  

 

⇒AC=8cm

AC=8cm=AE+EC=3.2+EC

EC=8−3.2=4.8cm

Also  

AB

AD

​  

=  

CB

ED

​  

 

∴  

AB

2.4

​  

=  

5

2

​  

 

AB=6cm=AD+DB=2.4+DB

⇒DB=3.6cm

So BD=3.6cm and CE=4.8cm