in the triangle ABC , D and E are point on the side AB and AC such that AD:DB=1:2 and AE:EC=1:2. what would be the ratio of the area of the triangle ADE and quadrilateral DECB?
Attachments:
Answers
Answered by
0
Answer:
The basic proportionality theorem states that if a line is drawn parallel to one side of a triangle and it intersects the other two sides at two distinct points then it divides the two sides in the same ratio.
It is given that AD=8 cm, AB=12 cm and AE=12 cm.
Using the basic proportionality theorem, we have
Step-by-step explanation:
AD
=
AC
AE
=
BC
DE
⇒
AB
AD
=
AC
AE
⇒
12
8
=
AC
12
⇒8AC=12×12
⇒8AC=144
⇒AC=
8
144
=18
Now, CE=AC−AE=18−12=6 cm
Hence, CE=6 cm.
Similar questions